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0.5+x-8x^2=0
a = -8; b = 1; c = +0.5;
Δ = b2-4ac
Δ = 12-4·(-8)·0.5
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{17}}{2*-8}=\frac{-1-\sqrt{17}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{17}}{2*-8}=\frac{-1+\sqrt{17}}{-16} $
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